In the following figure of a ship, ABDH and CEFG are two parallelograms. Find the value of x.
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i have let the point O where x is made
Angle ABD+ angle HDC = 180( linear pair)
so angle HDC = 50°
Angle GFE = Angle GCE ( opposite angles of parallelogram are equal)
so angle GCE= 30°
NOW,by using angle sum property of triangle
angle GCD+ angle HDC+ angle COD = 180 °
so,angle COD = 180-130-30
angle COD = 20°
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hope u got this one
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