in the following figure of triangle abc angle abc = 70°and angle ACB=60°. find angle ABD and angle ACE.
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angle ABD is 180-70=110°
angle ACE is 180-60=120°
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Answer:
∠ACE = 120°
∠ABD = 110°
Step-by-step explanation:
Given that :-
∠ abc = 70°
∠ACB - 60°
To find :-
∠ ABD = ?
∠ ACE = ?
Solution:-
since straight line = 180
∠abc = 70° and ∠ACB = 60°
Now, BE is straight ray
so ,
∠ACB + ∠ACE = 180°
60°+ ∠ACE = 180°
∠ACE = 180°-60°
∠ACE = 120°
Now, DC is straight ray
so ,
∠ABC+∠ABD = 180°
70° + ∠ABD = 180°
∠ABD = 180° - 70°
∠ABD = 110 °
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