In the following figures (i) to (vi), a pair of parallel lines are cut by a transversal. Find the size of each lettered angle
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Answered by
55
I) x=60 degree as vertically opposite angle
y=x so y=60
z=128 degree
2)
q=135 degree vertically opposite angle
p=180-135=45
3)
a=70
b=110
4)
x=180-128=52
y=52
z=128
5)
a=180-75=105
b=180-105=75
c=75
d=105
6)
q=180-62=118
p=62
r=118
s=62
that's all thx
y=x so y=60
z=128 degree
2)
q=135 degree vertically opposite angle
p=180-135=45
3)
a=70
b=110
4)
x=180-128=52
y=52
z=128
5)
a=180-75=105
b=180-105=75
c=75
d=105
6)
q=180-62=118
p=62
r=118
s=62
that's all thx
Answered by
36
i)x=60 opposite angles are equal
y= 60
ii)q = 45
p = 135
iii) a=70
b=110
iv)x=52
y=52
z=128
v)b=75
c=75
a=105
d=105
vi)p=62
s=62
q=118
r=118
y= 60
ii)q = 45
p = 135
iii) a=70
b=110
iv)x=52
y=52
z=128
v)b=75
c=75
a=105
d=105
vi)p=62
s=62
q=118
r=118
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