Question

In the following nuclear reaction, Identify unknown labelled X.
22/11 Na + X = 22Ne + Ve
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Answer 1

Answer:

X=electron

²²Na11 + X = ²²Ne10 + Ve

Answer 2

Given :

²²Na₁₁ + X = ²²Ne₁₀ + Ve

To find :

X = ?

Solution :

²²Na₁₁ + ᵇXₐ = ²²Ne₁₀ + Ve

Balance the equation by balancing the mass no. and atomic no.

Atomic no. :-  

11 + a = 10

a = 10 - 11

a = -1

Mass no. :-

22 + b = 22

b = 22 - 22

b = 0

So we can write X as ⁰X₋₁

We know that  ⁰X₋₁ represents electron (⁰e₋₁)

Therefore X is an electron(⁰e₋₁)

X = electron