Question

In the following reaction if 10 gram of Hydrogen reacts with Nitrogen what will be the volume of Ammonia at STP

Answer 1

Answer:

56.66 gram of ammonia.

Explanation:

Since, we know the reaction of hydrogen with nitrogen to give ammonia as N2+3H2->2NH3.

So, we get that 6 grams of hydrogen is reacting to form 34 gram of ammonia or for moles we have 3 moles of hydrogen reacts to form 2 moles ammonia.

So, 1 gram of hydrogen will have 34/6 gran of NH3.

Hence, 10 gram of hydrogen will have (34/6)*10 = 56.6 gram of ammonia.

So, moles of ammonia will be 56.6/17 which will be 3.3 moles so the volume of ammonia is 3.3*22.4 litres = 74.5 litre of volume.

Answer 2

Answer:

Volume of NH3 at STP = 74.67 litre

Explanation:

1         3             2.                 ( Moles)

N2  + 3 H2 ⇒ 2NH3

 

Given 10g of H2

n = weight\ Molecular weight = 10\2 = 5 mole of hydrogen for 2 mole of NH3

Produced moles of NH3 = 2\3 ×5 =10\3

Volume of NH3 at STP = 10\3 ×22.4 =74.67 L