In the following triangle ABC, ZB = 70°, ZBDE = 110°, BC = 5 cm , AE 3 cm and CE = 3 cm. Then the length of DE is
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2x−3y=13...(1)
7x−2y=20....(2)
Let us use the elimination method to the given system of equations.
Multiply (1) by 2 and (2) by 3. And subtract both the equations.
−17x=−344x−6y=2621x−6y=60−+−
x=−14−34=+2
Substitute the value of x in equation (1), we have
y=−3
Hence x=2 and y=−3
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