In the Garbar Jhala, Ahmadabad a shopkeeper first raises the price of
Jewellery by x% then he decreases the new price by x%. After one such up
down cycle, the price of a Jewellery decreased by Rs. 21025. After a
second updown cycle the Jewellery was sold for Rs. 484416. What was the
original price of the jewellery.
Answers
Answer:
The answer is 525625 Rs.
Step-by-step explanation:
Let the initial price = Rs 100,00p
Price after the first increment = 10000p + 100xp
Price after the first decrement = 10000p + 100xp -(100px + px^2)
= 100px - px^2
Now calculate the total decrement
px^2 = 21025.....(1)
Price after the second increment = 10000p - px^2 + 100xp - px^3/100
Price after the second increment = 10000p - p^2 + 100xp - p^3/100 -100xp +px^3/100 - px^2 +px^4/10000
= 10000p - 2px^2 +px^2/10000
= 484416 ....(2)
By solving equation 1 and 2 we get.
x = 20
By substituing the value of x we get
p = 525625
Thus the original price of the jewellery is 525625 Rs.