Question

in the gaven figure ab is the diameter were ap 12 cm pb 6cm taking the value of π3 find the perimeter of the shaded region

Answer 1

☺☺☺ Hope this Helps  ☺☺☺

Answer 2

Answer:

Perimeter of the shaded region is 10π+28 or 59.4 cm.

Step-by-step explanation:

Given information: AB is diameter, AP=12 cm, PB=6 cm.

The angle inscribed in a semicircle is a right angle. It means triangle APB is a right angled triangle.

Use Pythagoras theorem,

$AB=\sqrt{12^2+16^2}=20$

The diameter is 20 cm, so the radius of the semicircle is 10 cm.

The length of the arc AB is

$Arc(AB)=\pi r=10\pi=10\times (3.14)=31.4$

The perimeter of the shaded region is

$Perimeter=Arc(AB)+AP+PB$

$Perimeter=31.4+12+16=59.4$

Therefore the perimeter of the shaded region is 10π+28 or 59.4 cm.