in the give figure AB parallel to CD, angle APQ-60degree angle PRD-137degree.find x and y
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Answer:
it is given that ABII CD
so. APQ = PQR ( alternative interior
angles )
. PQR = 60 degree
PRD +/_PRD = 180 ( linear pair)
PRD = 180 - 137
PRD = 43
in Triangle PQR
PQR + / QPR +/_PRQ = 180 ( Angle sum property of triangle )
60 +/_ QPR + 43 = 180
QPR = 180 - 103
= 77
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