In the given change, MnoMn+2, there is transfer of
electrons __________.
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Answer:
Given reaction:
MnO
4
−
→MnO
2
Calculate the oxidation state of reactant and product as
Let the oxidation number of Mn be 'x'.
Oxidation number of O=−2.
in MnO
4
−
: x+4×(−2)=−1
x=−1+8 or x=+7
in MnO
2
: x+2×(−2)=0
x−4=0 or x=+4
Therefore Change in oxidation number = 7-4=3
The number of electrons involved in the conversion of MnO
4
−
to MnO
2
is 3.
Explanation:
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