Question

In the given circle, O is a
centre and angle BDC = 42°, then
angle ACB is equal to​

Answer 1

Answer:

48°

Step-by-step explanation:

As angle BDC = 42°

Angle DOC= 90° (angle formed inside a semicircle are 90°)

angleDOC +.angle OCD +angleCDO = 180°

90°+ OCD+42° =180°

132 +OCD = 180°

OCD = 180°-132°

OCD=48°