In the given circle, O is a
centre and angle BDC = 42°, then
angle ACB is equal to
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Answer:
48°
Step-by-step explanation:
As angle BDC = 42°
Angle DOC= 90° (angle formed inside a semicircle are 90°)
angleDOC +.angle OCD +angleCDO = 180°
90°+ OCD+42° =180°
132 +OCD = 180°
OCD = 180°-132°
OCD=48°
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