Math, asked by harsh4279, 5 months ago

In the given circle, O is a
centre and angle BDC = 42°, then
angle ACB is equal to​

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Answers

Answered by snehabarhate33
3

Answer:

48°

Step-by-step explanation:

As angle BDC = 42°

Angle DOC= 90° (angle formed inside a semicircle are 90°)

angleDOC +.angle OCD +angleCDO = 180°

90°+ OCD+42° =180°

132 +OCD = 180°

OCD = 180°-132°

OCD=48°

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