Physics, asked by hkj123, 1 year ago

in the given circuit find the potential of point E .pls show how to solve

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Answered by tiwaavi

Hello Dear.

Given ⇒

e.m.f.( =ε) = 8 V.
R₁ = 5 Ω
R₂ = 1 Ω

From the Figure we can observe that the Resistors are in series.

∴ R = R₁ + R₂
= 5 + 1
= 6 Ω

Using Ohm's law,

V = I × R
⇒ I = V/R
⇒ I = 8/6
∴ I = 4/3 A.

∵ Current remains same in the Series,
∴ Current flowing through the 1 Ω Resistors is 4/3 A.

Again Using the Ohm's law,

V = I × R
V = 4/3 × 1
∴ V = 4/3 V.

∴ Potential across the Point E is 1.33 A.

Hope it helps.

Anonymous: It is right bro, Potential across the Resistors of 1 ohm, same for the resistor of Point E. Because you must know that when current flows in the conductor It reaches the Point E in the last. Before Point E it reaches the 1 ohm Resistors where Potential is decreases now the potential will be same for the point E.

Anonymous: Because the Potential which was decreases in 1 ohm resistors now will not decrease as there is not any resistors after that, thus the Potential at point E will be the same as the potential in Resistor of 1 Ohm.

duttaditya18p3zry7: Isn't the potential at the negative terminal of the circuit always zero?

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