in the given circuit if the current flowning through the 3 ohm resistor is 1 A then find the potential difference across the battery and the current flowing.
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1/R =1/3 +1/6=1/2
R=2 ohm.
I=1 Ampere.
V=IR
V=1× 2= 2 V
R=2 ohm.
I=1 Ampere.
V=IR
V=1× 2= 2 V
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