Question

in the given circuit, the electric potential of P will be

Answer 1

Answer: (4). The electric potential of P will be 9 V.

Explanation:

Using formula for series of

$\dfrac{1}{C}=\dfrac{1}{C_{1}}+\dfrac{1}{C_{2}}+\dfrac{1}{C_{3}}$

$\dfrac{1}{C}=\dfrac{1}{3}+\dfrac{1}{1}+\dfrac{1}{2}$

$\dfrac{1}{C}=\dfrac{11}{6}$

$C = \dfrac{6}{11}$

According to figure,

Using potential division rule

For $3\mu F$

The potential is

$V_{1}=\dfrac{C_{eq}}{C_{1}}\times V$

$V_{1}=\dfrac{6}{11\times 3}\times11$

$V_{1}= 2$

The electric potential of P will be

$11-V_{P}=V_{1}$

$11-V_{P}=2$

$V_{P}=9 V$

Hence, The electric potential of P will be 9 V.