In the given circuit xl = 400 , xc = 300 and r = 100 . Then peak value of current and phase difference between voltage and current is
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Answer:
(a)The phase difference between current and voltage ϕ is given by
tanϕ=RXC−XL
XC=ωC1=500Ω
XL=ωL=100Ω
R=400Ω
Thus tanϕ=400400=1
⟹ϕ=45∘
(b) Power factor is given by cosϕ=1
⟹ϕ=0∘
⟹tanϕ=0
⟹XC=XL=100Ω
⟹C=10μF
Hence an 8μF capacitor need to be connected in parallel with the given capacitor.
Explanation:
None
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