Question

In the given diagram ‘O’ is the centre of the circle and AB is parallel to CD. AB = 24 cm and distance between the chords AB and CD is 17 cm. If the radius of the circle is 13 cm, find the length of the chord CD

Answer 1

Distance between two chords is perpendicular. Define distance as EF.

Let suppose OF as x then OE = ( 17 - x )

In ∆OAE

OA^2 = AE^2 + OE^2

${(13)}^{2} = {(x)}^{2} + {ae}^{2} \\ 169 - {ae}^{2} = {x}^{2} ..........(1)$

In ∆OCF

OC^2 = CF^2 + OF^2