Question

in the given diagram what is a centre in Bt is a tangent at b. oa║cb, ob and ac intersect at p.∠aob=45°,calculate ∠acb, ∠otb and apb

Answer 1

Answer:

triangle APO congruent triangle BPC BY AAA

then,

angle ACB = 45

THEN BY ANGLE SUM PROPERTY WE GET

angle CPB = 90

THEN ANGLE APB = 90(LINEAR PAIR)

NOW BY ANGLE SUM PROPERTY WE GET

180 = AOB + OTB + OBT

180 - 135 = OTB

OTB = 45

HOPE IT HELPS YOU.......

Answer 2

Answer is in the attachment.