In the given fig. AB parallel to CD find the value of x,y,z
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140
y=75 degree(alternate interior angle)
y+z=125(exterior angle property)
75+z =125
z=125-75
z=50 degree
y+x=180(linear pair)
75+x=180
x= 180-75
x= 105 degree
y+z=125(exterior angle property)
75+z =125
z=125-75
z=50 degree
y+x=180(linear pair)
75+x=180
x= 180-75
x= 105 degree
Answered by
0
y=75°, x= 105°, z=50°.
y=75°
(alternate interior angle)
y+z=125
(exterior angle sum property)
75+z =125
z=125-75
z=50°
y+ x=180
(linear pair of lines)
75+x=180
x= 180-75
x= 105°
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