Question

In the given fig,ABC is a tangent to a circle at B whose centre is O, PQ is a chord parallel to AC and angle QBC =65°, then find the value of angle PBQ...​

Answer 1

Step-by-step explanation:

As OQ⊥ PR

(radius ⊥ tangent) & AB∣∣PR

⇒AB⊥OL

and perpendicular from centre to chord bisects the chord.

⇒AL=BL,

∠QLB=∠QLA

& LQ=LQ\Rightarro$$ By SAS

congruency, ΔQLA≅ΔQLB

⇒∠AQL=∠BQL=20

o

(90

o

−70

o

)

⇒∠AQB=40

o

.