Question

in the given fig angle ADE =angle ABC AD 2cm DB =3cm AE =3cm then CE =

Answer 1

Answer:

Step-by-step explanation:

Given : AD= 7.6 cm, AE= 7.2 cm, BE= 4.2 cm, BC= 8.4 cm.

In ∆ADE and ∆ABC

∠A = ∠A (COMMON)

∠ADE = ∠ABC (GIVEN)

∆ADE~∆ABC (AA Similarity)

AD/AB = DE /BC

[Ratios of the corresponding sides of the similar triangles are equal]

AD/(AE+BE) = DE/BC

7.6 / (7.2+4.2)= DE/8.4

7.6 /11.4 = DE/8.4

DE= (7.6 × 8.4) /11.4

DE= (7.6×8.4)/11.4

DE = 63.84/11.4= 5.6 cm

Hence, DE= 5.6 cm

HOPE THIS WILL HELP YOU...

Answer 2

3cm is the right answer