In the given fig angle b = angle c and ab = ac . prove that be = cf
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The median AD, median BE and the perpendicular bisector CF which bisects angle C should meet at a point G which is 2/3 rd of median AD.
Point G is the center of gravity of a triangular lamina.
Angle b=c.
AD is medium then BD=DC.
In triangle ABD = ACD then BD= DC then AB= AC.
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