Question

In the given fig. AOB is a line, OD bisects angle AOC
and oE birects angle BOC. Show that angle DOE is a right angle.
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Answer 1

$\huge\mathfrak\pink{Answer}$

Solution:-

Since OP bisects ∠ BOC.

∴ ∠ BOC = 2(∠ POC) ...(1)

Again, OQ bisects ∠ AOC.

∴ ∠ AOC = 2(∠ QOC) ... (2)

Since ray OC stands on line AB.

∴ ∠ AOC + ∠ BOC = 180°

⇒ 2(∠ QOC) + 2(∠ POC) = 180°  [Using (1) and (2)]

⇒ 2(∠ POC + ∠ QOC) = 180°

⇒ ∠ POC + ∠ QOC = 90°

⇒ ∠ POQ = 90°

Hence ∠ POQ = 90°  Proved.

Answer 2

Answer:

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Step-by-step explanation:

good morning

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