Question

IN THE GIVEN FIG AOB is sector
OF L60 of A CIRCLE WITH CENTRE
O RADIUS = 17cm. IF API OBB
AP = 15 cm FIND AREA OF SHADED
REGION​

Answer 1

as APO is a right angle triangle right angled at P

then, OP^2 = AO^2 - AP^2

= 289. - 225

=64

OP= 4cm

Area of shaded region=Area of Sektor -Area of tri AOP

22/7 * 1/6* 17*17 - 1/2*15*8

= 91.38cm*cm