Question

In the given fig.BAC is a line find x. Hence find angle CAE and BAD

Answer 1

Solution:

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 To find:

The value of x,.
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As we know that, the total angle in a straight line equals 180°,

So,

We can say,

=> (3x - 5)°+ 55°+ (x + 20)°= 180°

=> 4x + 70° = 180°

=> 4x = 180° - 70°

=> 4x = 110°

=> x = 27.5°
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=>∠CAE = ( 3x -5 )°

=> ∠CAE = 3(27.5°) - 5°

=> ∠CAE = 82.5° -5°

=> ∠CAE = 77.5°

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∠BAD = x + 20°

∠BAD = 27.5° + 20°

∠BAD = 47.5°,.

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                                   Hope it Helps !!

Answer 2

Hey friend, Harish here.

Here is your answer:

Given that,

→ CAB is a line

→ ∠CAE = (3x-5)° ,  ∠EAD = 55° & ∠DAB = (x+20)°.

To find, 

The value of x.

Solution,

We know that,

$Sum\ of\ all\ angls\ in\ a\ line = 180$

→ $3x-5+55+x+20=180$

→$4x + 70 = 180$

→$4x= 180-70$

→ $4x=110$

→$x = \frac{110}{4}$

→$x = 27.5$

So, ∠CAE = 3x -5 = (3×27.5) -5 = 82.5 - 5 = 77.5°

      ∠BAD = x + 20 = 27.5 + 20 = 47.5°

Therefore ∠CAE is 77.5° & ∠BAD is 47.5°.
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Hope my answer is helpful to you.