Question

in the given fig. bc is a diameter. if AB=3cm AC=4cm and angle A=90 find the shaded region​

Answer 1

UR ANSWER IN THE ABOVE PIC

PLSS MRK BRAINLIEST

Answer 2

Answer:

The area of shaded region $(A)=13.64\text{ cm}^{2}$

Step-by-step explanation:

Given,

$AB=3\text{ cm}$

$AC=4\text{ cm}$

$\angle BAC=90^\circ$

Therefore,

$BC=\sqrt{AB^{2}+AC^{2}}\\\\\Rightarrow{BC}=\sqrt{3^{2}+4^{2}}\\\\\Rightarrow{BC}=\sqrt{9+16}\\\\\Rightarrow{BC}=\sqrt{25}\\\\\Rightarrow{BC}=5$

$BC=5\text{ cm}$

The Diameter of the circle $D=BC=5\text{ cm}$

The radius of the circle $r=2.5\text{ cm}$

Therefore,

The area of the circle

$(A_{1})=\pi\times{r}^{2}\\\\\Rightarrow{A_{1}}=\frac{22}{7}\times(2.5)^{2}\\\\\Rightarrow{A_{1}}=19.64\text{ cm}^{2}$

The area of Right angle Triangle

$A_{2}=\frac{1}{2}\times{h}\times{b}\\\\\Rightarrow{A_{2}}=\frac{1}{2}\times3\times4\\\\\Rightarrow{A_{2}}=6\text{ cm}^{2}$

The area of shaded region = Area of the circle - Area of the triangle

Therefore,

$A=A_{1}-A_{2}\\\\\Rightarrow{A}=19.64-6\\\\\Rightarrow{A}=13.64\text{ cm}^{2}$