Math, asked by dhar027269, 1 day ago

in the given fig find the value of x​

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Answers

Answered by jitendra12iitg
0

Answer:

The answer is x=\dfrac{ac}{b+c}

Step-by-step explanation:

Here angle M and angle N are 50^\circ \Rightarrow LM || PN

Thus angle L = angle P

Angle K is common to both triangles LMK and PNK

So \triangleLMK \sim \trianglePNK

\Rightarrow \dfrac{\text{LM}}{\text{PN}}=\dfrac{\text{MK}}{\text{NK}}\\\Rightarrow \dfrac{a}{x}=\dfrac{b+c}{c}\\\\\Rightarrow x=\dfrac{ac}{b+c}  

Answered by akshaypansari144
0

Answer:

x = c*a/(b+c)

Step-by-step explanation:

Triangle PNK and LMK are similar. Similar because Angle PNK and Angle LMK are same and Point K is common.

So PN/NK = LM/MK

x/c = a/(b+c)

x = c*a/(b+c)

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