Question

In the given fig three point charges are situated at the corner of an equilateral triangle of side 10 centimetre calculate the resultant force on the charge at B what is its direction

Answer 1

Answer:

9000N

Explanation:

Force = F

F= (1/9*10^9)*( (100^2*10^-12)/(0.1^2))

        =( 9*10^9 *10^4*10^-12)/ 10^-2

       =  9000N

Net Force on B =sq root( (9000)^2 + (9000)^2+2.(9000)^2* cos 120))

                          = 9000(sq root(1+1+2(-1/2))

                                 =   9000N (60 degree from horizontal)

Direction is 60 degree from horizontal.

Fig attached with post:

Answer 2

Answer:we know that from vector if angle between two is 120° and magnitude is equal then resultant is simply F then 9×10^9×10000×10000\100×100

Explanation:

Then 9× 10^3