In the given fig. XP and XQ are tangents from X to the circle with centre O. R is a point on the circle. Prove that XA + AR = XB + BR.
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GIVEN:
XP and XQ are tangents of the circle from with centre O and R is a point on the circle.
TO PROVE : XA + AR = XB + BR.
PROOF:
XP = XQ [X is an external point].......(1)
AP = AR [A is an external point]......(2)
BQ = BR [B is an external point]......(3)
From eq 1
XP = XQ
(XA + AP) = (XB + BQ)
XA + AR = XB + BR
[From eq 2 & 3 , AP = AR ,BQ = BR ]
Hence proved.
HOPE THIS WILL HELP YOU...
XP and XQ are tangents of the circle from with centre O and R is a point on the circle.
TO PROVE : XA + AR = XB + BR.
PROOF:
XP = XQ [X is an external point].......(1)
AP = AR [A is an external point]......(2)
BQ = BR [B is an external point]......(3)
From eq 1
XP = XQ
(XA + AP) = (XB + BQ)
XA + AR = XB + BR
[From eq 2 & 3 , AP = AR ,BQ = BR ]
Hence proved.
HOPE THIS WILL HELP YOU...
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