in the given figue o is the centre of the circle. bao=40 bco=30. find aoc
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In △ABO, AO=BO⇒∠BAO=∠ABO=30
o
In △CBO, CO=BO,⇒∠BCO=∠CBO=40
o
⇒∠ABC=∠ABO+∠CBO=30+40=70
o
Angle subtended at the center is twice the angle subtended anywhere on the arc, so,
∠AOC=2×∠ABC=140
o
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