in the given figure 0 is the centre of the circle and PA,PB are tangents to the circle .if angle APB=60degree,find angle ACB
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Angle APB = 60
Therefore reflex of angle AOB =120 by theorem obviously.
At O subtract 360 from 120 to get angle AOB
Now, angle AOB = 240°
Hence angle ACB =240/2
Therefore reflex of angle AOB =120 by theorem obviously.
At O subtract 360 from 120 to get angle AOB
Now, angle AOB = 240°
Hence angle ACB =240/2
kartikeyaa:
Angle sum of a quadrilateral
We get angle AOB =120
There fore ACB=120/2
That is 60°
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