Question

In the given figure a b and CD are common tangents to circles of an equal radius prove that a b equal to CD

Answer 1

Answer:

extend AB and CD to P

BP=CD (tangents to a circle from a point are equal)  ----(1)

AP=PC (tangents to a circle from a point are equal) ------(2)

subtract 1 and 2

AP-BP = PC-CD

AB = CD

hence proved

Step-by-step explanation: