in the given figure a b parallel to CD and a is equal to 65 degree find a c b s e d and ABC 10 number guys plz
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oliviashewfelt:
plz help me
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Your solution..................
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hey there!! here is ur answer...
BAC = ACB =65° [A.I.A ,since AB||CD]
ACB+ACD+ECD=180 [L.P]
ACB+65+52=180
ACB+117=180
ACB=180-117
ACB=63
now,
In ΔABC
ABC+ACB+BAC=180 [angle-sum property]
ABC+63+65=180
ABC+128=180
ABC=180-128
ABC=52
HOPE THIS HELP U....
BAC = ACB =65° [A.I.A ,since AB||CD]
ACB+ACD+ECD=180 [L.P]
ACB+65+52=180
ACB+117=180
ACB=180-117
ACB=63
now,
In ΔABC
ABC+ACB+BAC=180 [angle-sum property]
ABC+63+65=180
ABC+128=180
ABC=180-128
ABC=52
HOPE THIS HELP U....
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