In the given figure, a circle touches all the four sides of a quadrilateral ABCD with sides AB = 6 cm, BC = 7cm, and CD = 4 cm. Find AD.
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Hey Dear here is Your Answer =)
#)Let P,Q,R,S be the points where the circle touches the quadrilateral .From a point out side of the circle the two tangents to the circle are equal.
=>AP = AS,BP = BQ , CR = CQ , and DR = DS
=>Adding AP + BP + CR + DR = AS + BQ + CQ + DS
=>AB + CD = AD + BC
=>6 + 4 = AD + 7
=>AD = 3 cm .
Hope It helps You Out =)
Thanks (^^)
#)Let P,Q,R,S be the points where the circle touches the quadrilateral .From a point out side of the circle the two tangents to the circle are equal.
=>AP = AS,BP = BQ , CR = CQ , and DR = DS
=>Adding AP + BP + CR + DR = AS + BQ + CQ + DS
=>AB + CD = AD + BC
=>6 + 4 = AD + 7
=>AD = 3 cm .
Hope It helps You Out =)
Thanks (^^)
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