In the given figure, a solid consists of a cone
and a hemisphere with a common radius 6
cm. If the height of the cone is 10 cm, then
the volume of the whole solid is
o
26411 cu. cm
26411 cu. cm
28811 cu. cm
528rt cu cm
Answers
Answer:
Step-by-step explanation:
For the cylinder we have
Radius of the base=r=60cm
Height =h=180cm
Volume of water that the cylinder contains =V=πr
2
h={π×60
2
×180}cm
3
For conical part, we have
Radius of the base =r=60cm
Height =h
1
=120cm
Volume of conical part V
1
=
3
1
πr
2
h
1
=
3
1
π×60
2
×120cm
3
={π×60
2
×40}cm
3
For hemispherical part, we have
Radius =r=60cm
Volume of the hemisphere V
2
={
3
2
π×60
3
}cm
3
⇒V
2
={2π×60
2
×20}cm
3
=(40π×60
2
)cm
3
Hence volume of the water left out in the cylinder
⇒V=V
1
−V
2
={π×60
2
×180−π×60
2
×40−40π×60
2
}cm
3
=π×60
2
×{180−40−40}cm
3
=
7
22
×3600×100cm
3
=
700
22×36
m
3
=1.1314m
3
Answer:
28811 cu.cm
Step-by-step explanation:
Thanks