In the given figure, a triangle ABC has been given in which AB = 7.5 cm, AC = 6.5 cm and BC = 7 cm. On base BC, a parallelogram DBCE of the same area as that of AABC is constructed.
Find the height DL of the parallelogram.
Answers
Answer:
Height DL = 3 cm
Step-by-step explanation:
Given : The sides of triangle are AB = 7.5 cm , AC = 6.5 cm, BC = 7 cm
A parallelogram DBCE is constructed on base BC.
Area of parallelogram = Area of triangle ABC ----- ( i )
Since all the sides of triangle are of different sizes
Therefore Area of triangle ABC = √(s(s-a)(s-b)(s-c))
where s is semi perimeter given by s= (a+b+c)/2
and a, b and c are the sides of triangles
s= (a+b+c)/2 = (7.5 +6.5+7)/2
s= 21/2=10.5 cm
Area of triangle ABC = √(10.5(10.5-7.5)(10.5-6.5)(10.5-7))
= √(10.5*3*4*3.5)
= √441
= 21
Area of triangle ABC = 21 cm^2
Area of parallelogram is given by = base * height
21 = 7 * DL
DL = 21/7
DL = 3 cm
Therefore height DL of Parallelogram = 3 cm
Answer:
3 is the right answer
Step-by-step explanation:
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