Question

in the given figure, AB = 66° and ACD = 60°. If bisector of A meets BC at D, then find ADB.

Answer 1

angle (a+b+c )=180°.66°+60°+a= 180°.a=180°-126°》54°.in triangle ABD ,angle ADB=180°-(66°+54°/2)=180°-93°=87°.