In the given figure, AB=AC and AD is the bisector of ∠BAC. Then ∆ADB ≅ ∆ADC by
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Answer: ASA
Step-by-step explanation:
<BAD = <CAD (AD is bisector.)
AB = AC (Given)
⇒<ABD = <ACD (AB = AC so ΔABC is isosceles.)
So by ASA ΔABD ≅ ΔACD
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