Question

In the given figure AB=AC and angle ACD=105°,find angle BAC

Answer 1

Answer:

Sol: By linear pair property,

 ABE +  ABC = 180°

139° +  ABC = 180°

 ABC = 180° - 139°

 ABC = 41°

Again , BY Linear pair property,

 ACD +  ACB = 180°

156° +  ACB = 180°

 ACB = 180° - 156°

 ACB = 24°

Now ,In ABC , By Angle Sum Property of Triangle ABC +  BAC +  ACB = 180°

41° +  BAC + 24° = 180°

 BAC = 180 ° - 65°

 BAC = 115°