Question

In the given figure, AB = AC, DAB = EAC. Prove that AD = AE.
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Answer 1

We know that, in a triangle, angles opposite to equal sides are equal.

Hence, in ∆ABC, since AB = AC

therefore, angle ABC = angle ACB ... (i)

using exterior angle theorems in ∆DAB and ∆ EAC

angle ABC = angle DAB + angle ADB

angle ACB = angle EAC + angle AEC

substituting these values in (i)

angle DAB + angle ADB = angle EAC + angle AEC

(angle DAB and angle EAC cancel out because they're equal)

angle ADB = angle AEC

we know that, in a triangle, sides opposite to equal angles are equal.

Hence, AD = AE

... Hence Proved!

Answer 2

Answer:

proved

Step-by-step explanation:

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