Question

In the given figure,AB=AC,DB=DC,prove that angleABD and angleACD​

Answer 1

In ∆ABC , we have

.

(angles opposite to equal sides)

Again in ∆DBC , we have

DB = DC................(given)

.

(angles opposite to equal sides)

Hence we obtain ,

${ \angle}ABC - { \angle}DBC = { \angle}ACB - { \angle}DCB$

Thus gives ,

${ \angle}ABD = { \angle}ACD \: \: (hence \: \: proved)$

Answer 2

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