In the given figure AB BC and CD are equal chords of a circle with the centre o and AD is the diameter if angel DEF is 110 degree find angle AEF and angle FAB.
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Step-by-step explanation:
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Step-by-step explanation:
m∠AEF = 20°
Step-by-step explanation:
Foe better understanding of the solution, see the attached diagram of the problem :
Given : AB = BC = CD, AD is the diameter of the circle.
m∠DEF = 110°
To find : m∠AEF
Solution : Since, AD is the diameter of the circle
⇒ m∠AED = 90° ( Angle formed in the semicircle is 90°)
Now, m∠AEF + m∠AED = m∠DEF
m∠AEF + 90° = 110°
⇒ m∠AEF = 110° = 90°
⇒ m∠AEF = 20
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