Question

in the given figure AB=BC=CD=DE and AOB=40°,where OB is the radius of the circle. then find the value of reflex AOE.​

Answer 1

Answer:

Given that:

∠COD=40

∘

,CD=DE=EF=GF

To find:

reflex ∠COG=?

Solution:

∠COD=∠DOE=∠EOF=∠FOG=40

∘

(Equal chord makes equal angles at the centre.)

∠COG=∠COD+∠DOE+∠EOF+∠FOG=4×∠COD

=4×40

∘

=160

∘

Reflex ∠COG=360

∘

−160

∘

=200

∘