In the given figure, AB||CD and EF _|_ AB. If EG is the transversal such that angle GED = 130°, find angle EGF
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GED=GEF+FED
130=GEF+90
GEF=40
AND GEF+GEC =90
GEC=50
GEC=RGF=50
130=GEF+90
GEF=40
AND GEF+GEC =90
GEC=50
GEC=RGF=50
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This is the solution of the sum
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