In the given figure, AB || CD. Find the value of x
(Hint: Through M draw EMF |AB|| CD.)
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hi there.. here's the answer for your question
Step-by-step explanation:
Draw a line through point C and name it as FG where FG || AE We know that CG || BE and CE is a transversal From the figure we know that ∠GCE and ∠CEA are alternate angles So we get ∠GCE = ∠CEA = 20o It can also be written as ∠DCG = ∠DCE – ∠GCE By substituting the values we get ∠DCG = 130o – 20o By subtraction we get ∠DCG = 110o We also know that AB || CD and FG is a transversal From the figure we know that ∠BFC and ∠DCG are corresponding angles So we get ∠BFC = ∠DCG = 110o We know that FG || AE and AF is a transversal From the figure we know that ∠BFG and ∠FAE are corresponding angles So we get ∠BFG = ∠FAE = 110o ∠FAE = x = 110o Therefore, the value of x is 110.
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