In the given figure AB||CE , CE||EF. Find the value of x.
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ABIICF,consider those two lines and keep BC as the transversal
which gives angle BCF to be 40° (alternate interior angles are equal)
65°+40°+y=180(angles in a straight line)
105°+y=180°
y=75°
x and y are corresponding angles of the transversal CF in lines CD and EF
:.x=y=75°
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here's ur answer I hope this helps u
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