Question

In the given figure, AB // DC and AD // BP. If the area
of trapezium ABCD is 95 sq. cm and the area of
ABCP = 15 sq. cm then find the area of ACAB.Ans: 40 cm​

Answer 1

Answer:

ADC = 90°

Ab parallel to dc

ab = 15 cm

cd = 40cm

ac = 41 cm

Using Pythagoras Theorem 

ad² + dc² = ac²

ad² + 40² = 41²

ad² + 1600 = 1681

ad = √1681- 1600

ad = √81

as = 9 cm

area of trapezium =1/2 × (base1 + base2) × h

                              1/2× ( 15 + 41) × 9

                          = 247.5 cm² 

Answer 2

Answer:

In the given figure, AB // DC and AD // BP. If the area

of trapezium ABCD is 95 sq. cm and the area of

ABCP = 15 sq. cm then find the area of ACAB.Ans: 40 cm