In the given figure, AB=DE and BF = EC., prove that AC=DF.
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Given:
AB=DE and BF = EC
To prove:
AC=DF
PROOF:
In the given figure
∠B = ∠E = 90°
So let us consider
ΔABC & ΔDEF
- AB=DE [given]
- ∠B = ∠E = 90° [ given]
BF = EC
BF+CF = EC+CF
from the figure
- BC = EF
ΔABC ≅ ΔDEF (SAS)
then,
- AC = DF [by CPCT]
Hence proved
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