Question

In the given figure, AB=DE and BF = EC., prove that AC=DF.​

Answer 1

Given:

AB=DE and BF = EC

To prove:

AC=DF

PROOF:

In the given figure

∠B = ∠E = 90°

So let us consider

ΔABC & ΔDEF

• AB=DE [given]
• ∠B = ∠E = 90° [ given]

BF = EC

BF+CF = EC+CF

from the figure

• BC = EF

ΔABC ≅ ΔDEF (SAS)

then,

• AC = DF [by CPCT]

Hence proved