Question

In the given figure , AB > AC and angle ABD = angle ACD . Prove that BD > DC .​

Answer 1

Answer:

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Step-by-step explanation:

In △ABC, we

AB=AC⇒∠ABC=∠ACB

Again in △DBC,

DB=DC .

⇒∠DBC=∠DCB

∠ABC−∠DBC=∠ACB−∠DCB.

∠ABD=∠ACD.