Question

in the given figure ab is a diameter of circle with Centre O and ac is the tangent to the circle at take if angle BAC is equal to 130 degree then find angle if you

Answer 1

angleAOC=180-130=50
angle A=90
therefore angle ACO=180-(90+50)
=40

Answer 2

angleAOC=180-130=50

angle A=90

Now in triangle AOC

angle ACO=180-(90+50) (By angle sum property)

=40