in the given figure AB is perpendicular to BC at B find the value of x
Attachments:
Answers
Answered by
5
X+20+2x+1+7x-11=90
10x+10=90
10x=80
X=8
10x+10=90
10x=80
X=8
roman52:
sir its correct brilliant
Answered by
6
Seg AB is perpendicular to Seg BC.
i.e. angle ABC=90°
now; x+20+2x+1+7x-11=90°
10x+10=90°
10x=90-10
10x=80°
hence x=80/10
x=8
i.e. angle ABC=90°
now; x+20+2x+1+7x-11=90°
10x+10=90°
10x=90-10
10x=80°
hence x=80/10
x=8
Similar questions